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Sort data in flash from back end php in as3

i have this code that adds event listeners for button’s onclick
private function addEventListeners()
{
addEventListener(MouseEvent.CLICK,buttonClick);
}

private function buttonClick(e:MouseEvent):void{
e.target.x=100;
e.target.y=100;
}

it works fine when there is only 1 button but i have a problem when there is more than 1, for example :
private function addEventListeners()
{
addEventListener(MouseEvent.CLICK,buttonClick);
addEventListener(MouseEvent.CLICK,buttonClick);
addEventListener(MouseEvent.CLICK,buttonClick);
addEventListener(MouseEvent.CLICK,buttonClick);
}

private function buttonClick(e:MouseEvent):void{
e.target.x=100;
e.target.y=100;
}

in this case the listners are added in order they are created why this happens?
And is there a way to sort the listner’s by name, first the button with name=”xyz” then by name=”abc”?

A:

if (e.target == e.currentTarget) return; // handle single target
e.target.x = 100;
e.target.y = 100;

that’s how you would only set the x, y, or both if it’s the current target

e.currentTarget
This property is only meaningful when event is dispatched by
the MouseEvent.MOUSE_OVER_OR_OUT_OF_FRAME event type.
The properties of the Event object may be defined in either event
or target. If both types are specified, the event type is
MOUSE_OVER_OR_OUT_OF_FRAME.

Also, if

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But I need to output each character only once.
eg:
I want to get,
>dievamp>wWWweehMadaenteertingRaacuten
But my output currently is :
>diewamp>wWWweehMadaenteertingRaaacuten
Thanks in advance.

A:

Something like this should work
Dim input As String

‘Split the text into an array.
Dim tokens() As String = Split(input, “A series of trails between Woods Lake on the north and Lake Duncan on the south.

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Why does neither sqrt(a) nor a work to the power of 2?

Alright, so I am trying to figure out why do we always say that
$$
\sqrt{a}
otin \mathbb{R} \quad \text{for} \quad a \in \mathbb{R}
$$
This makes sense, I can completely see why this is true. But I am curious as to why
$$
a^{2}
otin \mathbb{R}
$$
Because multiplying by the number, a^2 is really just a, that is the reason why this statement doesnt make sense. As an example:
$$
\sqrt{3}=\sqrt{3}^{2}